In the diagram below of ΔACD, B is a point on AC⎯⎯⎯⎯⎯such that ΔADB is an equilateral triangle, and ΔDBC is an isosceles triangle with DB⎯⎯⎯⎯⎯≅BC⎯⎯⎯⎯⎯. Find m∠C. Explain your work/thought process.

The isosceles triangle ΔDBC have equal base angles.

The measure of angle C is 30 degrees

ΔADB is an equilateral triangle.

So, we have:

Next, we calculate

-- angle on a straight line

So, we have:

ΔDBC is an isosceles triangle.

So, we have:

This is then calculated as:

Divide both sides by 2

Hence, the measure of angle C is 30 degrees

Read more about triangles at:

link

equilateral triangle all angles add up to 180 and are equal so each angle is 60 degrees

angles on a line add up to 180.

angle CBD = 180-60 = 120

DBC is an isosceles triangle so it's base angles are the same.

180-120= 60

60/2=30

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

ans789

step-by-step explanation: