A military cannon is placed at the base of a hill. The cannon is fired at an angle toward the hill. The path of the cannon ball is parabolic and can be represented by y = -0.05x² + 5x + 1, where y represents
the height of the ball in meters and x represents the horizontal distance of the ball from the cannon.
The incline of the hill can be represented by the equation y = 0.725x. How far will the cannon ball have
moved horizontal from the cannon when it hits the hill?

9514 1404 393

  85.7 meters

Step-by-step explanation:

A graphing calculator finds the result easily. The ball moved 85.7 meters horizontally before it hit the hill.

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Equating y expressions gives ...

  0.725x = -0.05x^2 +5x +1

In standard form, this is ...

  0.05x^2 -4.275x -1 = 0

The quadratic formula tells us the positive solution is ...

  x = (4.275 +√(4.275^2 -4(0.05)(-1)))/(2(0.05)) = (4.275 +√18.475625)/.1

  x ≈ 85.733

The cannon ball hits the hill at a horizontal distance of 85.7 meters from the cannon.

add an !

step-by-step explanation:

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )