What is an equation of the line that passes through the point (2,-5) and is parallel to the line 6x + y = 6?

Step-by-step explanation:

Hey there!

Given equation is; 6x + y= 6.

6x + y -6=0……(i)

Slope (m1) = (-coefficient of X)/(coefficient. of y)

Slope (m1) = (-6)/(1)

Therefore, slope of the equation is -6.

As per the condition of parallel lines, slope of 1st equation is equal to 2nd equation.

Therefore, m1=m2= -6

The another straight line passes through the point (2,-5). So to find the equation, use one-point formula.

(i.e (y-y1) = m2(x-x1)).

So, the equation is;

(y+5) = m2(x-2)

Now, we know that m1=m2= -6. Let's keep its value on it.

y+5 = -6(x-2)

Or, y+5 = -6x +12

Or, 6x+ y -7 = 0

Therefore, the equation which is parallel to 6x + y= 6 equation and passes through the point (2,-5) is 6x+y-7=0.

Hope it helps...

answer:

c. the third graph

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.