Find two consecutive even integers such that the sum of the smaller and 3 times the larger is 330 I am so stuck please any one help

The 2 numbers = 81 and 83

Step-by-step explanation:

As, one number = x

The other, because it's an even number and consecutive = x + 2

So the larger numbef here is x + 2

And they are saying 3 times x + 2 plus x = 330

So let's solve!

3 times x + 2 = 3(x+2) = 3x + 6

So we will add it to x = (3x + 6) +(x) = 4x + 6

So they are saying the sum of them will be 330

So, 4x + 6 = 330

4x = 330 - 6

4x = 324

x = 324/4

x = 81

So x is the first number = 81

And the second is x + 2 = 81 + 2 = 83

So the 2 numbers are 81, 83

Lets check!

3 times the bigger number = 83 x 3 = 249

We will add it to 81 and we will get 330

So, 249 + 81 = 330

So the answer is right

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead