In a certain board game, a 12-sided number cube showing numbers 1–12 is rolled. If three such number cubes are rolled, what is the probability that at least 1 of them shows a 2? 0.0006
0.2297
0.7703
0.9994

0.7703

Step-by-step explanation:

The easiest way to calculate this is to find the probability that none of the cubes show a 2. The probability that a cube doesn't show a 2 is 11/12.

0.7703. Now we have to subtract this value from one which gives us 0.2297. Hope this helps

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb

ƒ = 0.03b

hope this ( :

step-by-step explanation: