PLEASE HELP The half-life of phosphorous-32 is approximately 24.3 days.
How much of a 3 gram sample of phosphorus-32 would remain after 10 days?
ROUND TO THREE DECIMAL POINTS.

Step-by-step explanation:

We will use the standard formula for half-life:  

Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.

So, we will substitute 1/2 for a and 24.3 for d. This yields:

We have a 3 gram sample. Therefore, our initial amount A₀ is 3:

And we want to find the remaining sample after 10 days. So, t=10. Substitute:

Use a calculator. So:

Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.