PLzzz help meee In rhombus MATH, the coordinates of the endpoints of the diagonal MT are M(0, 2) and T(4, 6). Write an equation of the line that contains diagonal AH. Give your answer in slope-intercept form.

y = - x + 6

Step-by-step explanation:

-- Rhombus diagonals are perpendicular and bisect each other.

-- A( , ) and B( , )

Coordinates of the midpoint of a segment AB are

( , )

and formula of a slope of the line segment AB is

m =

-- If AB ⊥ CD then × = - 1

-- Slope-point of linear equation is

y - = m( x - )

~~~~~~~~~~~~~~~~

M(0, 2)

T(4, 6)

= = 1

= - 1

Coordinates of the intersection of the diagonals are ( , ) = (2, 4)

y - 4 = - 1(x - 2)

y = - x + 6 is slope-intercept form of the diagonal AH

table a is wierd

step-by-step explanation:

6*f

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant