A skyscraper is 396 meters tall. At a certain time of the day, it's casts a shadow that is 332 meters long. At what angle is the sun above the horizon at that time?

56.96°

Step-by-step explanation:

The set up will give a right angles triangle where;

The height of the sky scraper = hypotenuse side = 396m

The length of the shadow will be the opposite = 332m

According to the SOH trig identity

sin theta = opp/hyp

sin theta = 332/396

sin theta = 0.8383

theta = arcsin 0.8383

theta = 56.96°

Hence the sun is at 56.96° above the horizon

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

i believe it's a.

i'm not sure on this one, most likely correct.