If h(x) = g[f(x)], use the table of values for f, g, f'and g' to find the value of h'(1). x f(x) g(x) f'(x) g'(x)
1 3
2
2
6
2 1
00
5
7
3
7
2
7
9
your answer goes here

Hey there :)

h ( x ) = f [ g ( x ) ]

To find h ' ( x )  

We do → f ' [ g ( x ) ] × g ' ( x )  

This is called the chain rule

Given;

g ( 1 ) = 2  →  f ' ( 2 ) = 5

g ' ( 1 ) = 6

Apply the formula

h ' ( 1 ) = f ' [ g ( 1 ) ] × g ' ( 1 )

          = f ' ( 2 ) × 6

          = 5 × 6

h ' ( 1 ) = 30

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐