Function 1: Sam is 150 feet below sea level in a cave and trying to climb back out to safety at zero elevation. He climbs at a rate of 4 feet per minute. This situation can be modeled with a function where C(m) represents the number of feet he has left to climb in order to reach
zer elevation
Function 2: The function below shows the number of feet that Sam's friend, Arthur, has left to climb
to reach zero elevation from a different cave as a function of time x in minutes). Assume that the domain is represented by all real numbers for
0 < 30
X
f(x)
5
-125
10
-100
15
-75
20
-50
25
-25
30
0
Who climbs at a faster rate? Make sure to explain your answer and how you know

Start at -150, then add 3(-5), then add 122.2. -150 + 3(-5) + 122.2 = -45.3.

The answer is -45.3 feet depth. while minus sign shows the descend under the water with water surface as starting point.

Step-by-step explanation:

Initial depth of diver under the water =-150feet=−150feet

Diver descends 5 feet per minute for 3.5 minutes =3.5*(-5)=3.5∗(−5)

                                                                                =-17.5=−17.5

Note: minus sign shows that the diver is under the water.

Diver ascends =122.2feet=122.2feet

Now adding all the terms a below as a numerical expression.

Current Depth of Diver after he descends 5 feet for 3.5 minutes and ascend 122.2 feet after  =-150-17.5+122.2=−150−17.5+122.2

                           =45.3feet=45.3feet

By taking the initial depth of diver from which we add or subtract the changes made when he ascends or descends in the water to get the current depth.

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step-by-step explanation: