Two stores have movies to rentthe first store charges a $12.50-per-month membership fee plus$1.50 per movie rentedthe second store has no membership fee but charges $3.50 per movierented. what is the minimum number of movies a person would need to rent in a monthfor the first store to be a better deal?

Step-by-step explanation:

We know that the first store charges $12.50 per month, which is a initial condition, and charges additionally $1.50 per movie, which is variable, this represents the ratio of change, so this can be expressed as

Where represents movies.

Now, the second store doesn't charge and membership fee, just it charges a cost per movie which is $3.50.

Then, to solve the minimum number of movies needed to Plan A be the best choice, we just have to solve the following inequality

Which expresses the case where Plan A is a better choice, solving for , we have

Which means that the minimum number of movies is 7, which is the next whole number after 6.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

b

step-by-step explanation: