2(2x - 8) > 4(3x - 12) Solve the inequality (Just like my previous problem) Make sure to show work!!

x < 8

Step-by-step explanation:

This is a special case, so at the end of the equation we'll flip the sign.

Distribute:

2 * 2x = 4x

2 * -8 = -16

4x - 16

4 * 3x = 12x

4 * -12 = -48

12x - 48

4x - 16 > 12x - 48.

Subtract 12 from both sides.

12 - 12 = 0

4x - 12x = -8x

-8x - 16 > -48

The additive inverse of subtraction is addition so do -16 + -48, which equals -64

-8x/-8 = x

-64/-8 = 8

Now this is where we flip our sign so here we go :)

x < 8

There.

Hope this helped and sorry if I'm wrong.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true