A coin is tossed and ​six sided die numbered 1 through 6 is rolled. Find the probability of tossing a tail and then rolling a number greater than 1.

5/12

Step-by-step explanation:

A coin has two faces (H, T)

n(S) = 2 (sample space)

If it is tossed and a rail is gotten,

n(E) = 1 (event)

Probability of tossing a tail = n(E)/n(S)) = 1/2

If a dice is rolled, the sample space S = {1, 2, 3, 4, 5, 6}

n(S) = 6

Number greater than 1 are the evens E = {2, 3, 4, 5, 6}

n(E) = 5

pr(rolling a number greater than 1) = 5/6

Hence  the probability of tossing a tail and then rolling a number greater than 1 = 1/2 * 5/6

= 5/12

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

19

step-by-step explanation: