An experiment involves studying the composition of genders of a set of triplets. What is the \nprobability that there are 2 boys and a girl in the set?

37.5%

Step-by-step explanation:

The computation is shown below:

Here we assume that the 1st, 2nd and 3rd child be the triplet and it could be either a girl or boy

Now

B = Boy

G = Girl

The possible triplets are

(BBB) (BBG) (BGB) (BGG) (GBB) (GBG) (GGB) (GGG)

These are 8 triplets

Now find the sets that involves 2 boys and a girl

(BBG) (BGB) (GBB)

Now the probability is

P = 3 ÷ 8

= 37.5%

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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