In the diagram below, \overline{OH} OH start overline, O, H, end overline is parallel to \overline{ID} ID start overline, I, D, end overline. Find the length of \overline{HD} HD start overline, H, D, end overline.

HP=11

Step-by-step explanation:

Now that we have \blueE{HP}HPstart color #0c7f99, H, P, end color #0c7f99, we can find HDHDH, D.

\begin{aligned} HD&=\blueE{HP}+DP &=\blueE{2}+9 &=11 \end{aligned}

HD

=HP+DP

=2+9

=11

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752