Marcus has saved $340 to buy a new tablet. All of his money is in the form of $10 and $20 bills. He has 5 more $20 bills than $10 bills. How many of each type of bills does Marcus have? Let x represent the number of $10 bills and y represent the number of $20 bills.

For $10 bill = 8 bills

For $20 bill = 13 bills

Step-by-step explanation:

X = $10

Y = $20

Y = x + 5

So, total $20 bill = $20(x+5)

Total $10 bill = $10(x)

Total = $20(x+5) + $10(x) = 340

$20x + 100 + $10x = $340

$30x + 100 = $340.

$30x = $340 - 100

$30x = $240

X = $240/$30

X= 8

So no. Of 10 bill = 8

No. Of 20 bill = 8+5= 13

So, $10 X 8 = $80

So, $20 X 13 = $260

So total = $80 + $260 = $340

So, Marcus have for $10 bill is "8"

And for $20 bill is "13"

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

bfgbh bhf gfdzf bhgfrdfgbn cvdgsytrghvn ncvhgfdtrseawa hgdrsxcvbgfrewq

step-by-step explanation: