Point P′(−3, 2) is the image of point P(3, 8) under a translation. What
is the image of (0, −6) under the
same translation?

The image of (0, -6) after the same transformation is (-6, -12)

Step-by-step explanation:

After the required translation, the given image of the given point P(3, 8) is P'(-3, 2)

Therefore, the translation of preimage P(3, 8) to the image P'(-3, 2) is given by the difference between the coordinates as follows;

The translation from P(3, 8) to P'(-3, 2) = T(-3 - 3, 2 - 8) = T(-6, -6)

Therefore after the same translation, the preimage of (0, -6) will have an image given as follows;

Coordinate of preimage (0, -6) → T(-6, -6) (0, -6) = (0+ -6, -6 + -6) → Coordinate of image (-6, -12)

The image of (0, -6) after the same transformation = (-6, -12).

answer: finding the extract measurements and knowing the points

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.