The length y of a rectangle is four less than three times the width x. The perimeter of the rectangle is 16 cm.

There is no requirement in the question. I'll calculate the area of the rectangle to help you with this question.

Step-by-step explanation:

System of Equations

Let's call y to the length of a rectangle, x to its width. There are two conditions that will help us to solve for x and y.

Divide by 2:

To solve the system, we'll substitute the y in the first equation into the second:

Joining like terms:

Solving:

Find the value of y:

Thus, the length of the rectangle is 5 cm and its width is 3 cm. The area is calculated as:

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft