How many different 10-letter permutations can be formed from 8 identical H's and two identical T's?

Step-by-step explanation:

Given 10 letters with 8 identical H's and two identical T's, the number of different permutations will be expressed as;

Hence the number of different 10-letter permutations that can be formed from 8 identical H's and two identical T's is 45

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2