Estimate the number of school-aged children in the city where the population is approximately 60,000, if 1 of every 10 citizens is a school-aged child. If 500 children can attend each school, about how many schools will the city need?

1 out of 10 are school aged.

Divide total population by 10:

60,000 / 10 = 6,000 are school aged.

Each school holds 500, divide school aged by 500:

6,000 / 500 = 12

They would need 12 schools.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

c and d is your answers.

stay frosty!