Mei and Anju are sitting next to each other on different horses on a carousel. Mei’s horse is 3 meters from the center of the carousel. Anju’s horse is 2 meters from the center. After one rotation of the carousel, how many more meters has Mei traveled than Anju? π more meters 2π more meters 4π more meters 5π more meters

After one rotation the number of meters mei has traveled than Anju is 2·π

Step-by-step explanation:

The given parameters are;

Distance of Mei from the center of the carousel, = 3 m

Distance of Anju's horse from the center of the carousel, = 2 m

We note that the motion of the carousel is circular and their distance from the center of the carousel is the radius of the circle in which Mei and Anju will move

The distance they will move is the circumference of the circle = 2 × π × r

The distance traveled by the Mei in one rotation = 2 × π × = 2 × π × 3 = 6·π

The distance traveled by the Anju in one rotation = 2 × π × = 2 × π × 2 = 4·π

After one rotation, the difference in distance traveled by Mia and Anju = 6·π - 4·π = 2·π

Therefore, after one rotation the number of meters mei has traveled than Anju = 2·π.

the answer is 31.27mph

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: