Find the value of p so that the quadratic solution x(2 x+p) + 8 = 0 has real and distinct roots

p = -17, x = 8

p = -10, x = 1

p = -10, x = 4

p = 10, x = -1

Step by Step:

x (2 x + p) + 8 = 0

x = 1/4 (-sqrt(p^2 - 64) - p)

Hope I helped!

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x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x