The bus fare in a city is $2.00. People who use the bus have the option of purchasing a monthly coupon book for $28.00. With the coupon book, the fare is reduced to $1.00. Determine the number of times in a month the bus can be used so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book

56 = 56

Step-by-step explanation:

Given:

Bus fare = $2.00

coupon book = 28.00

bus fare w/ coupon book = $1.00

let x be the number of bus rides.

2.00x = 1.00x + 28.00

2.00x - 1.00x = 28.00

1x = 28.00

x = 28.00

24 bus rides for both to have the same cost.

2.00x = 1.00x + 28

2.00(28) = 1.00(28) + 28

56 = 28 + 28

56 = 56

answer: plz put a pic in so i can answer it

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w