Evaluate the function f(x) at the given numbers (correct to six decimal places). f(x) = 7e^x − 7 − 7x/x^2, x = 1, 0.5, 0.1, 0.05, 0.01, −1, −0.5, −0.1, −0.05, −0.01 f(1) = f(0.5) = f(0.1) = f(0.05) = f(0.01) = f(−1) = f(−0.5) = f(−0.1) = f(−0.05) = f(−0.01) = Guess the value of the limit of f(x) as x approaches 0, correct to six decimal places. (If an answer does not exist, enter DNE.) lim 7ex − 7 − 7x/x^2 = x→0

the correct answer is d

hope this

207/8 is the right

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.