Solve 10-5x+1=7x+11-12

x=1

Step-by-step explanation:

Let's solve your equation step-by-step.

10−5x+1=7x+11−12

Step 1: Simplify both sides of the equation.

10−5x+1=7x+11−12

10+−5x+1=7x+11+−12

(−5x)+(10+1)=(7x)+(11+−12)(Combine Like Terms)

−5x+11=7x+−1

−5x+11=7x−1

Step 2: Subtract 7x from both sides.

−5x+11−7x=7x−1−7x

−12x+11=−1

Step 3: Subtract 11 from both sides.

−12x+11−11=−1−11

−12x=−12

Step 4: Divide both sides by -12.

−12x

−12

=

−12

−12

x=1

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)