A company assigns to each of its employees an ID code that consists of one or two uppercase letters followed by a digit from 0 through 9. How many employee codes does the company have available?

7020 codes

Step-by-step explanation:

For one upper case letter:

There are 26 letters in this scenario

For two upper case letters:

There are 26 * 26 letters in this scenario. Essentially, there are 676 letters in this scenario.

For one upper case letter:

There are 10 digits that can be applied to it. So therefore, there are 26 * 10 codes in this case.

That means, there are 260 codes for one upper case letter.

For two upper case letters:

There are 10 digits that can be applied to it. That is to day, there are 676 * 10 codes in this case.

This means, for two upper case letters, there are 6760 codes.

Finally, we add up the number of codes for one upper case letter, and that of two upper case letters together. As such, we have

6760 + 260 = 7020.

The company has 7020 codes available.

Please vote for brainliest.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

a framing bias

step-by-step explanation:

rodrigo is subject to a framing bias i believe.