The area of a rectangle is (x2 - 5x - 36). What is the width if the length of the rectangle is (x + 4)?

Step-by-step explanation:

The width of the rectangle is (x - 9)

(x + 4)(x - 9)

x^2 - 9x + 4x - 36

x^2 - 5x - 36

W = ( x - 9 )

Step-by-step explanation:

The area of a rectangle is equal to the length times the width of the rectangle.

So we can say A = LW

A = (x^2 - 5x - 36)

L = (x + 4)

A = LW

W = A / L

W = (x^2 - 5x - 36) / (x + 4)

W = (x + 4) (x - 9) / (x + 4)

W = (x - 9)

Cheers.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

wth is with the little mtn top and what are you talking about like fix your words and accually make sence with them and i like was in a completly different question like three times like it seems like your ilitteret