a submarine is 50 meter below sea levl. it goes up 15 meters, then goes down 40 meters. what is the submarine' new position relative to sea level ? 1. ( -105 meters) 2. ( -75meters) 3.( -35 meters) 4. ( 25 meters)

-75 meters

Step-by-step explanation:

First, subtract 15 from 50, since it is going up:

50 - 15

= 35

Then, add 40, since it is going back down:

35 + 40

= 75

So, the new position is -75 meters relative to sea level

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb