Kyle challenges you to a game. Each player rolls a standard number cube twice. If the sum of the results is divisible by 3, you win. If it is not, Kyle wins. What is your probability of winning? Is this a fair game?

The game is not a fair game

Step-by-step explanation:

We start by listing out the sample space

Number Cube 1: {1,2,3,4,5,6}

Number Cube 2: {1,2,3,4,5,6}

Sample Space (S) of the sum of the 2 cubes;

Next, is to list out all multiples of 3; Represent this with M

Your probability of winning is the probability of M and is calculated as thus;

The probability of Kyle winning, P(K) = 1 - P(M)

The game is not a fair game because;

The probability of you winning and the probability of Kyle winning are not equal;

the answer is b 1/10

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