Two passengers leave the airport at kansas city, missouri. one flies to los angeles, california, in 3.4 hr and the other flies in the opposite direction to new york city in 2.4 hr. with prevailing westerly winds, the speed of the plane to new york city is 60 mph faster than the speed of the plane to los angeles. if the total distance traveled by both planes is 2464 mi, determine the average speed of each plane.

 x = 400 MPH    x+60 = 460 MPH

Step-by-step explanation:

(Distance = (Rate)(Time)

Let x = speed of the LA bound plane

Then, x+60 = speed of NYC bound plane

Sum of distances = 2464

3.4x + 2.4(x+60) = 2464

         5.8x + 144 = 2464

                  5.8x = 2320

                      x = 400 MPH    x+60 = 460 MPH

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.