9) Wilbur wants to make 7.6 gal. of a 35% alcohol solution by mixing together a 80%
alcohol solution and a 20% alcohol solution.
How much of each solution must he use?

1.9 gallons of 80% and 5.7 gallons of 20%

Step-by-step explanation:

x gallons of 80% alcohol solution is mixed with y gallons of 20% alcohol to make 7.6 gallons of 35% alcohol solution.

Based on the given, we get two equations:

Let's substitute y with y = 7.6 - x:

Then we find the value of y:

So the answer is:

1.9 gallons of the 80% solution.

5.7 gallons of the 20% solution,

Step-by-step explanation:

Let the volumes of the 80% and 20 % solutions be x  and y gallons.

Then:

x  +  y = 7.6.

Also, using amounts of pure alcohol:

0.8x + 0.2y = 7.6 * 0.35

0.8x + 0.2y = 2.66           Multiplying this equation by -5:

-4x - y = - 13.3                   Adding this to the first equation:

-3x = -5.7

= 1.9 gallons.

y = 7.6 - 1.9

=  5.7  gallons.

2x^2+5x+17

your welcome. : )