The two triangular prisms shown are similar. The dimensions of the larger prism were multiplied by a
scale factor of to create the smaller prism.
When the large prism was reduced, the surface area
changed by a factor of
125
10
8
25
8
10
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8
10
10
8

 The surface area is reduced by a factor of 16/25

Step-by-step explanation:  The area is the square measurements. So squaring the factor of the linear measurement change is the quick way is to determine the factor for the area.

The longer way-- if you had to prove your conclusion:

Compute the area of each side, add all the five sides of the prisms and find the ratio.

The area of the large prism is 500 square units.

The area of the smaller prism is 320 square units

320/500 = 32/50,  reduce again  16/25

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4