A radio signal travels at 3.00 * 10^8 meters per second. how many seconds will it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.54 * 10^7 meters? show all the steps that you used to solve this problem. 1

0.118 seconds

Step-by-step explanation:

Data are given in the question

Radio travels meters per second = 3.00 × 10^8

Distance = 3.54 × 10^7 meters

Based on the given information, the number of seconds required to takes radio signal from the satellite to the surface of the earth is

As we know that

So,

= 0.118 seconds

We simply applied the general formula to determine the number of seconds taken

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560