Harris Interactive® conducted a poll of American adults in August of 2011 to study the use of online medical information. Of the 1,019 randomly chosen adults, 60% had used the Internet within the past month to obtain medical information. Use the results of this survey to create an approximate 95% confidence interval estimate for the percentage of all American adults who have used the Internet to obtain medical information in the past month.

The 95% confidence interval for the true proportion would be given by (0.570;0.630) .

And if we convert this into % we got (57.0%, 63.0%)

Step-by-step explanation:

The information given we have the following info given:

represent the sampel size

represent the sample proportion of interest

The confidence level is 95%, our significance level would be given by and . And the critical value would be given by:

The confidence interval for the mean is given by the following formula:  

Replacing the info given we got:

The 95% confidence interval for the true proportion would be given by (0.570;0.630) .

And if we convert this into % we got (57.0%, 63.0%)

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1