Lewis needed to find the difference in lengths between the hypotenuse and the longest leg of this triangle. His work is shown below. Triangle A B C. Side B C is 16 and side A C is 12. Hypotenuse A B is labeled c. 12 squared + 16 squared = c squared. 144 + 256 = c squared. 400 = c squared. StartRoot 400 EndRoot = c. 200 = c. Difference: 200 minus 12 = 188. What errors did Lewis make? Check all that apply. He simplified StartRoot 400 EndRoot incorrectly. It should be 20 instead of 200. He found the difference between the hypotenuse and the short leg instead of the long leg. He evaluated 12 squared incorrectly. It should be 12 (2) = 24. He evaluated 16 squared incorrectly. It should be 16 (2) = 32. He should not have taken the square root of each side to get rid of the exponent.

its an acute right triangle

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -