Please help me I need this done I need someone who will SHOW WORK and complete all the questions for 15 points please help me if you can!

see below

Step-by-step explanation:

1a) Area of rectangle = L * W

A = 57*35 = 1995 in²

1b) A =L * W = 8 * 14.3 = 114.4 cm²

1c) Area of Δ =1/2 base x height

Height is always perpendicular to the base!!!

base = 36; height = 15

A of Δ = (1/2) * 36 * 15 =18*15 = 270 m²

1d) Area of Δ =1/2 base x height

 base = 27.3; height =  16.8

A of Δ = (1/2) * 27.3 * 16.8 = 229.32 rounded to  final answer 229.3 in²

1e)  Area of Δ =1/2 base x height

   base = 14; height = 9

A of Δ = (1/2) * 14 * 9 = 7 * 9 = 63 yd²

1e)  Area of Δ =1/2 base x height

   base =30 ; height = 40

In this case base also can be 40 and height 30 b/c it's right Δ

A of Δ = (1/2) * 30 * 40 = 15 * 40 =600 ft²

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.