A2.50 kg flower pot is pushed out a window this is at a height of 12.0m onto a spring with a spring constant of 800.n/m. how much does the spring compress if the ball comes to a stop.

0.86 m

Explanation:

We can solve the problem by using the law of conservation of energy.

The initial mechanical energy of the flower pot is just gravitational potential energy, given by:

where

m = 2.50 kg is the mass of the pot

g = 9.8 m/s^2 is the acceleration due to gravity

h = 12.0 m is the height

When the pot hits and compresses the spring coming to a stop, all this energy is converted into elastic potential energy of the spring:

where

k = 800 N/m is the spring constant

x is the compression of the spring

Due to the conservation of energy,

So we can write

seeing the graph would

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2