A right circular cylinder has a radius of 6 inches and a height of 4 inches. Decrease the height and radius by 10% each, then find the percent change in surface are given the equation for the surface area of a cylinder is:
SA = 2(pi)rh + 2(pi)r^2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

thats not a system of equations, that is a solution