![Mathematics](/tpl/images/cats/mat.png)
Simplify (write without the absolute value sign):
|xβ(β12)|
, if x<β12
![answer](/tpl/images/cats/otvet.png)
![Answer](/tpl/images/cats/otvet.png)
-3
step-by-step explanation:
a drawing really does here:
so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be). so point b is at (-2,2). point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).
now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.
we have the area of the triangle is .5bh=12.5
we know the base length is 5 (ab)
we have the height is (2-y) if you look at your
plug in
.5(5)(2-y)=12.5
solve for y to get the y-coordinate for c
2.5(2-y)=12.5
divide both sides by 2.5 giving:
2-y=5
now subtract 2 on both sides
-y=3
y=-3
![Answer](/tpl/images/cats/otvet.png)
10 down (bang1)
5 up
5down (2)
2.5 up
2.5 down (3)
1.25 up
1.25 down (4)
now add them up : )
hoped i lol
![Answer](/tpl/images/cats/otvet.png)
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