H(t)=t^2+4t+3 what are the zeroes of the function? Write the smaller t first, and then the larger t second

t = - 3, t = - 1

Step-by-step explanation:

Given

h(t) = t² + 4t + 3

To find the zeros equate h(t) to zero, that is

t² + 4t + 3 = 0

Consider the factors of the constant term (+ 3) which sum to give the coefficient of the t- term

The factors are + 3 and + 1, since

3 × 1 = 3 and 3 + 1 = 4, thus

t² + 4t + 3 = (t + 3)(t + 1) = 0

Equate each factor to 0 and solve for t

t + 3 = 0 ⇒ t = - 3

t + 1 = 0 ⇒ t = - 1

smaller zero is t = - 3

larger zero is t = - 1

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

bfgbh bhf gfdzf bhgfrdfgbn cvdgsytrghvn ncvhgfdtrseawa hgdrsxcvbgfrewq

step-by-step explanation: