Question 9. Factor x^2 - 6x + 9.
A
(x - 3)
B
(x - 3)(x + 3)
C
(x - 3)^2
D
9x + 3)^2

C

Step-by-step explanation:

Given

x² - 6x + 9

Consider the factors of the constant term (+ 9) which sum to give the coefficient of the x- term (- 6)

The factors are - 3 and - 3, since

- 3 × - 3 = + 9 and - 3 - 3 = - 6, thus

x² - 6x + 9 = (x - 3)(x - 3) = (x - 3)² → C

a²-2*a*b+b²=(a-b)²

x²-6x+9=x²-2*x*3+3²=(x-3)²  C)

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

what is the question?

step-by-step explanation: