When a coordinate grid is superimposed on a map of Harrisburg, the high school is located at (17, 21) and the town park is located at (28, 13).
If each unit represents 1 mile, how many miles apart are the high school and the town park?

13.6miles

Step-by-step explanation:

Using the formula for calculating the distance between two points

D = √(y2-y1)²+(x2-x1)²

When a coordinate grid is superimposed on a map of Harrisburg with the high school located at (17, 21) and the town park is located at (28, 13), our points are

P1 = (17,21)

P2 = (28,13)

x1 = 17, y1 = 21, x2 = 28, y2 = 13

Distance between the coordinates

D = √(28-17)²+(13-21)²

D = √11²+(-8)²

D = √121+64

D = √ 185

D = 13.6miles

The high school and the town park are 13.6miles apart

3 is greater then both of those numbers

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)