(3rd time Asking) Please help me with these questions!!!

(a) Water balloon 1 has height at time

and water balloon 2 has height

Both water balloons are moving straight downward, so their distance is equal to

(b) When both water balloons are at the same height, we have . So you could set both quadratic expressions equal to each other and solve for . Or you can use the fact that, when they're at the same height, the distance between them is 0. So using the expression from part (a), we have

or 1.75 seconds after being thrown/dropped.

At this time, they are both at a height of :

feet.

(c) The second and fourth statements are true.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

v,jhvljh,b.b; hk; ljujb,vuvccklokll; k,m,km,

step-by-step explanation: