An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. After how long will it reach its maximum height? What is the maximum height?
A. After 4 seconds the object will reach its maximum height of 58.8 seconds
B. After 5 seconds the object will reach its maximum height of 38.3 seconds
C. After 6 seconds the object will reach its maximum height of 58.8 seconds
D. After 2 seconds the object will reach its maximum height of 78.4 s

2. An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground?

A. -2 seconds
B. 2 seconds
C. 6 seconds
D. 78.4 seconds