If f(x)=x-3/x, g(x)=x+3, and h(x)==2x+1, what is (g*h*f)(x)?
A) (g*h*f)(x)=3x-6/x
B) (g*h*f)(x)=6x-6/x
C) (g*h*f)(x)=2x+4/2x+7
D) (g*h*f)(x)=8x+1/2x+1

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

no

step-by-step explanation:

(2,6)

step-by-step explanation:

cause i just did this and got the answer

you're welcome