Analysis showed that the mean arrival rate for vehicles at a certain Shell station on Friday afternoon last year was 4.5 vehicles per minute. How large a sample would be needed to estimate this year's mean arrival rate with 98 percent confidence and an error of ± 0.5? (Round the standard deviation answer to 4 decimal places. Enter your answer as a whole number (no decimals). Use a z-value taken to four decimal places in your calculations.) Sample size

The sample size needed is n=25.

Step-by-step explanation:

We will use a Poisson process to model the arrival.

We know the mean rate of arrivals, that is

The standard deviation is calculated as:

The z-value for a 98% CI is z=2.3262.

If the 98% CI has to be within a error of 0.5, we have:

The sample size needed is n=25.

you need more information to answer this question

step-by-step explanation:

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles