How do you solve equations through substitution and using inverse operations?
2+ 2(4+3) +4 + 4n= 200

n = 45

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

2+2*(4+3)+4+4*n-(200)=0

Step  1  :

Pulling out like terms :

  -180 + 4n  =   4 • (n - 45)

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    4   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    n-45 = 0

Add  45  to both sides of the equation :

                     n = 45

One solution was found :

                  n = 45

Processing ends successfully

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(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

your answer would be 10x - 1