An object is thrown upward at a speed of 96 feet per second by a machine from a height of 14 feet off the ground. The height of the object after t t seconds can be found using the equation h ( t ) = − 16 t 2 + 96 t + 14 h(t)=-16t2+96t+14. Give all numerical answers to 2 decimal places.

Where:

a= 8, b =-48, c = -7 and replacing we got:

And since the time cannot be negative the correct answer for this cae would be t = 6.142 s

Step-by-step explanation:

If the question is: When will the object hit the ground at when the time is how many seconds?

We have the function for the heigth given by:

And we want to find the time where so we can set like this the condition:

And we can rewrite the expression like this:

We can divide both sides of the equation by 2 and we got:

And we can use the quadratic equation to solve for t like this:

Where:

a= 8, b =-48, c = -7 and replacing we got:

And since the time cannot be negative the correct answer for this cae would be t = 6.142 s

Step-by-step explanation:

Below is an attachment containing the solution.

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64