A compound shaft consists of brass segment (1) and aluminum segment (2). Segment (1) is a solid brass shaft with an allowable shear stress of 69 MPa. Segment (2) is a solid aluminum shaft with an allowable shear stress of 86 MPa. If a torque of TC = 23900 N-m is applied at C, determine the minimum required diameter of the brass shaft d1 and the aluminum shaft d2.

A) The minimum required diameter of the brass shaft D₁ = 0.00176 m

B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m

Step-by-step explanation:

Data:

A compound shaft has two segments made of brass and aluminium

Allowable shear stress of Brass = 69 MPa.

allowable sheer stress of Aluminium = 86 MPa.

Torque TC = 23900 N-m

Find: Minimum required diameter of the brass D₁ and Auminium D₂

Solution: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.

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