The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there are 1200 after 1 day, what is the size of the colony after 22 days? How long is it until there are 40 comma 00040,000 mosquitoes? What is the size of the colony after 22 days?

This is a simple Arithmetic Progression question, and we will use the formula:

Step-by-step explanation:

From the question, we started with 1,000 mosquitoes, this is the first term ().

The next term is 1,200.

This means that the Common Difference () is:

1,200 - 1,000 = 200.

The term () we are looking for is 22.

So we have:

= 1,000

= 22

= 200

We solve as follows:

= 1,000 + (22-1)200

= 1,000 + (21)200

= 1,000 + 4,200

= 5,200.

So therefore, after 22 days, the number of mosquitoes in the colony will be 5,200 mosquitoes.

For the other question, we will use the value 40,000 mosquitoes.

We solve thus;

since it took 22 days to get to 5,200 mosquitoes, it will therefore take days to get 40,000 mosquitoes

22 days = 5,200 mosquitoes

days = 40,000 mosquitoes

we cross multiply thus:

22 x 40,000 = 5,200 x

880,000 = 5,200

making the subject, we have:

=

= 169

Therefore, it will take 169 days to get 40,000 mosquitoes.

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.

{3 + i, 3 - i, 3, -1}

step-by-step explanation: